(x+2)(x^2-9x+5)=0

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Solution for (x+2)(x^2-9x+5)=0 equation: 


Simplifying
(x + 2)(x2 + -9x + 5) = 0

Reorder the terms:
(2 + x)(x2 + -9x + 5) = 0

Reorder the terms:
(2 + x)(5 + -9x + x2) = 0

Multiply (2 + x) * (5 + -9x + x2)
(2(5 + -9x + x2) + x(5 + -9x + x2)) = 0
((5 * 2 + -9x * 2 + x2 * 2) + x(5 + -9x + x2)) = 0
((10 + -18x + 2x2) + x(5 + -9x + x2)) = 0
(10 + -18x + 2x2 + (5 * x + -9x * x + x2 * x)) = 0
(10 + -18x + 2x2 + (5x + -9x2 + x3)) = 0

Reorder the terms:
(10 + -18x + 5x + 2x2 + -9x2 + x3) = 0

Combine like terms: -18x + 5x = -13x
(10 + -13x + 2x2 + -9x2 + x3) = 0

Combine like terms: 2x2 + -9x2 = -7x2
(10 + -13x + -7x2 + x3) = 0

Solving
10 + -13x + -7x2 + x3 = 0

Solving for variable 'x'.

The solution to this equation could not be determined.

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